Question

Factor 16x2 + 24x + 9.

Answer 1

Use the identity (a+b)^2 = a^2 + 2ab + b^2
16x^2 + 24x + 9
= (4x)^2 + 2(4x)(3) + 3^2
= ... ?

Answer 2

answers
(16x + 3)(x + 3)
(4x + 3)(4x - 3)
(4x + 3)^2

Answer 3

Can you try first?

Answer 4

the second one

Answer 5

Nope....
As I've said, use the identity (a+b)^2 = a^2 + 2ab + b^2
From 16x^2 + 24x + 9 = (4x)^2 + 2(4x)(3) + 3^2, can you deduce what a and b is

Answer 6

what does deduce mean

Answer 7

deduce => guess

Answer 8

ok

Answer 9

4 and 3

Answer 10

16x2 + 24x +9
16x^2 and 9 are both perfect squares...0f 4x and 3
twice their product is 24 x ,so the polynomial fits condition of being a perfect sq.
16x^2 + 24x 9 = (4x + 3)^2

Answer 11

3 is correct for b
4 is not correct though ...

Answer 12

so t has to be 16

Answer 13

3 and 16

Answer 14

Compare the general form and the things you get
\[a^2 + 2ab + b^2\]\[ (4x)^2 + 2(4x)(3) + 3^2\]
can you see what is a and b clearly?
You've made a right guess for b... what is a?

Answer 15

2

Answer 16

Nope..

Answer 17

then it has to be 4

Answer 18

It has to be 4x :P

Answer 19

oh ok

Answer 20

Put a= 4x and b = 3 into (a+b)^2. You can get your answer~

Answer 21

ok thank you