Question

A circle has a radius of 6 in. The circumscribed equilateral triangle will have an area of:

Answer 1

do you have a figure? i mean is the triangle inside or outside the circle?

Answer 2

No it just asking this

Answer 3

I think the circle is inside the tringle

Answer 4

Circumscribed means outside. Inside would be inscribed.

Answer 5

The height of the equilateral triangle will be \[\frac 3 2 \times 6 = 9\]

Length of the side \( = 9 \times \frac 2 {\sqrt{3}}=6\sqrt{3} \)

Answer 6

Area \(= \frac 12 6\sqrt{3} \times 9 =27\sqrt{3} \; in^2\)

It's still early in the morning so make sure that my algebra is correct.

Answer 7

But the process is right.

Answer 8

My answer is suppose to be \[XXX \sqrt{X}\]

Answer 9

i have to fill in the x

Answer 10

X=3

Answer 11

\[3\times 3\times 3\times \sqrt{3} \]

Answer 12

Do you understand?

Answer 13

The three x is a big number

Answer 14

I have computer work and it grades it show half correct

Answer 15

I get 12sqrt(3) for the side-length:


The height would then be the longer leg of a 30-60-90 triangle, 6sqrt(3)*sqrt(3) = 6*3 = 18
A = 1/2 b h
= 1/2 18 * 12sqrt(3)
= 9 * 12sqrt(3)
= 108sqrt(3)