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Given the terms a1=5 and a4=14 of an arithmetic sequence, what is a20?
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@jim_thompson5910
a[4] - a[1] = 14 - 5 = 9 So d = 9/3 = 3. This means we're adding 3 to each term to get the next term ------------------------------- a[n] = a[1] + (n-1)*d a[n] = 5 + (n-1)*3 a[n] = 5 + 3n-3 a[n] = 3n + 2 So the nth term is 3n+2 This means that the 20th term is 3n+2 3*20+2 60+2 62 So the 20th term is 62
So a20 = 62
Thank you sooo much! =)
you're welcome again:)
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