last question.. promise :) A ball is tossed from a window that is 10 feet off the ground. The height, h (in feet), of the ball at any time, t (in seconds), is given by the equation h = - 16t^2 + 12x + 10. What is the maximum height (in feet) that the ball will reach? Type the number only in the box, do not put measurement units.
guess what? it is once again \(-\frac{b}{2a}\) this time \[-\frac{12}{2\times (-16)}\]
your fraction reduces to \(\frac{3}{8}\)
do i solve after that?
replace \(x\) by \(\frac{3}{8}\)
don't you differentiate it for the maximum?
nope
our miss brooks is not taking calc, she is taking algebra
i thought u squared the denominator?
nope
\[-\frac{b}{2a}\] there is no square
so for max i just put 3/8
replace \(t\) by \(\frac{3}{8}\) get \(\frac{49}{4}\) as your answer
12.25?
\(\frac{3}{8}\)is not the max, it is the number that you use to find the max
yes, 12.25
yayyy thanks sooo much :)
you done?
yes i just needed the max
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