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Mathematics 20 Online
OpenStudy (anonymous):

Select all of the following that are quadratic equations. x2 - 2x = 4x + 1 x3 - 6x2 + 8 = 0 5x - 3 = 0 2x2+ 12x = 0 5x - 1 = 3x + 8 9x2 + 6x - 3 = 0

OpenStudy (anonymous):

are you copy pasting all of your homework?

OpenStudy (anonymous):

no just the ones i dont know

OpenStudy (anonymous):

what is an quadratic equation?

OpenStudy (anonymous):

@shahzadjalbani: Please don't give away answer. This is against our code of conduct. Thanks

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

Alrght, coming back to the question. Any polynomial of order 2 is a quadratic equation.

OpenStudy (anonymous):

Quadratic Equation Ax2 + Bx + C = 0

OpenStudy (anonymous):

formula^?

OpenStudy (anonymous):

Right, so is this quadratic: \(x^3 - 6x^2 + 8 = 0 \)

OpenStudy (anonymous):

@tylertriebs nOW SELECT the equations having this order

OpenStudy (anonymous):

the 2nd,4th,and last

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

No.

OpenStudy (anonymous):

y

OpenStudy (anonymous):

It has a \( x^3\) term

OpenStudy (anonymous):

Quadratic equation is one whose greatest degree of a variable is 2 Like x2+2x+1

OpenStudy (anonymous):

oh i get so the first # has to squared @FoolForMath

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Now determine which are the quadratic equations.

OpenStudy (anonymous):

and it should be the order of that polynomial.

OpenStudy (anonymous):

ok so then it would be the 1st 4th and last

OpenStudy (anonymous):

Note: \(Ax+bx^2+c\) is also quadratic.

OpenStudy (anonymous):

Yes @tylertriebs Now you are right.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ok i got it thanks guys

OpenStudy (anonymous):

a quadratic equation is also a perabula right

OpenStudy (anonymous):

Yes and it's graph is lik |dw:1338547647540:dw|

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