Mathematics
20 Online
OpenStudy (anonymous):
Select all of the following that are quadratic equations.
x2 - 2x = 4x + 1
x3 - 6x2 + 8 = 0
5x - 3 = 0
2x2+ 12x = 0
5x - 1 = 3x + 8
9x2 + 6x - 3 = 0
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
are you copy pasting all of your homework?
OpenStudy (anonymous):
no just the ones i dont know
OpenStudy (anonymous):
what is an quadratic equation?
OpenStudy (anonymous):
@shahzadjalbani: Please don't give away answer. This is against our code of conduct. Thanks
OpenStudy (anonymous):
Ok
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Alrght, coming back to the question. Any polynomial of order 2 is a quadratic equation.
OpenStudy (anonymous):
Quadratic Equation
Ax2 + Bx + C = 0
OpenStudy (anonymous):
formula^?
OpenStudy (anonymous):
Right, so is this quadratic:
\(x^3 - 6x^2 + 8 = 0 \)
OpenStudy (anonymous):
@tylertriebs nOW SELECT the equations having this order
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
the 2nd,4th,and last
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
No.
OpenStudy (anonymous):
y
OpenStudy (anonymous):
It has a \( x^3\) term
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Quadratic equation is one whose greatest degree of a variable is 2 Like x2+2x+1
OpenStudy (anonymous):
oh i get so the first # has to squared @FoolForMath
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Now determine which are the quadratic equations.
OpenStudy (anonymous):
and it should be the order of that polynomial.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok so then it would be the 1st 4th and last
OpenStudy (anonymous):
Note: \(Ax+bx^2+c\) is also quadratic.
OpenStudy (anonymous):
Yes @tylertriebs Now you are right.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
ok i got it thanks guys
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
a quadratic equation is also a perabula right
OpenStudy (anonymous):
Yes and it's graph is lik
|dw:1338547647540:dw|