Question

Integrate 1/(3-e^x) using the substitution u=3-e^x
the answer is what i got but with 3-e^x instead

Answer 1

i got the answer \[1/3(\ln((-e^x)/(-3+e^x)))\]

Answer 2

i got ln(3-ex)+x

Answer 3

divide that by 3...sry

Answer 4

erm... when i differentiate that i got \[(-2e^x+3)/(3-e^x)\] which is not what is given by the question

Answer 5

divide that by 3 srry

Answer 6

lol which one?

Answer 7

ur ans 1/3(ln(3-e^x)+x)