Question

]How many liters of fluorine gas can react with 32.0 grams of sodium metal at standard temperature and pressure? Show all of the work used to find your answer.

2Na + F2 2NaF

Answer 1

n= m/M = 1,4mol
n(Na):n(F2) = 2:1
n(F2) = 2*1,4 = 2,8 mol
n= V/Vm -> V= n * Vm = 2,8 * 22,4 = 62,72 dm3

Answer 2

sorry made misstake n(F2) = 1/2 n(Na) = 0,7 mol V= 15,68 dm3

Answer 3

Thank you so much! i really did not get it. but now i understand it.

Answer 4

not a problem, glad to help