The tangent to the curve y=(sinx)/(1+tanx) at x =0 is parallel to y axis parallel to x axis
@satellite73 @FoolForMath
take derivative, replace \(x\) by 0
yes i got the answer as 0 now wat to do
@satellite73
are you sure it is zero? hold on a sec
u plzz check it
i think the slope is 1, so it is neither parallel to y or x axis
if the answer is one then it is equally inclined to x and y axis...
??? can u tell me
@experimentX
@eseidl
if the answer is one then it is equally inclined to x and y axis...???????
The derivative is: \[y'=\frac{(cosx)(1+tanx)+sinx(\sec^2x)}{(1+tanx^2)}\]at x=0 we get\[f'(0)=\frac{1}{1}=1\]So, yeah, it is neither parallel to the x-axis nor parallel to the y-axis as satellite73 stated.
so is it equally inclined to x and y axis
yeah. I also have a typo in my answer. the denominator should be (1+tanx)^2
o is it equally inclined to x and y axis
The slope of the tangent is parallel to the line y=x. You could also say it is equally inclined to the x and y axes.
if it is 0 then slope is parallel to x axis??????
If the slope of the tangent was equal to zero, then yes, it would be parallel to the x-axis
In this case the slope is parallel to the line y=x (actually it is parallel to any line y=x+b, b=constant).
so it wont be equally inclined to x and y axis? so the answer is none of these
plzz add this option too equally inclined to x and y axis
As I said, it is equally inclined to the x and y-axes.
|dw:1338565545401:dw|
Join our real-time social learning platform and learn together with your friends!