Question

A compound consists of 3.47 grams of oxygen and 1.52 grams of nitrogen. What is the empirical formula of this compound?
a. NO
b. N2O2
c. N2O
d. NO2

Answer 1

Did you change the grams to moles so you know the molar relationship?

Answer 2

3.47 g O = .2166 mole O atoms
1.52 g N = .1096 mole N atoms
Ratio :
\[\frac{.2166 mole O atoms}{.1096 mole N atoms}=\frac{1.995}{1}=\frac{2 O}{1 N}\]

Answer 3

Empirical Formula:
\[NO _{2}\]