write down an expression, in terms of n, for the nth term formula of the sequence? 0,3,8,15,_____
@experimentX @dpaInc @ParthKohli
its not common?
0,3,8,15, ... every term is of 3+2(n) more than the previous term
bro, how do u get it? are there any methods? please try to help?
where do iget the general formula for this?
It would be (n^2+3n-4)/2.
how do u get it/
should be n(n+2)
Use the second difference formula: a+d(n-1)+1/2(n-1)(n-2)c where a=first term, d=difference of first two terms c=second common difference
wow...i never came across this...where did u get this?
The internet! :D I forgot the website though.
how do u simplify this 1/2(n-1)(n-2)c?
(n^2-3n+c)/2
Do not replace 'n'. Just put 2 in place of c. Since it is the second common difference. 0--3 is 3| 3--8 is 5| The difference of 3 and 5 is 2.
do u have a webste for this, where did u search it?
I lost the link to the website I found it. But you can go through this one: http://www.skoool.co.za/studynotes/maths/id635.htm It has a few examples.
Oh ... i didn't know they were called quadratic sequence and have formula ...
HAHA! You know it now. No worries! :D
it is (n^2-1) thanks alot @emcrazy14 for your method...:DDDD, and @experimentX u too for trying to help me:)
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