If the dimensions of a rectangle become one-fifth of the original dimensions, then area of the new rectangle will be _______of the area of the original rectangle.
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OpenStudy (anonymous):
@saifoo.khan do you know how to find this? :)
OpenStudy (saifoo.khan):
That's cake.
OpenStudy (anonymous):
Can I use any numbers, as long as it's a fifth?
OpenStudy (saifoo.khan):
that's a general formula.
But let's break it down.
OpenStudy (saifoo.khan):
Hold on.
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OpenStudy (anonymous):
Okay :)
OpenStudy (anonymous):
I don't understand the formula. Can you try to explain it? I'm sorry
OpenStudy (saifoo.khan):
It's okay. i know it's confusing coz i modified it. hehe
OpenStudy (saifoo.khan):
Let me find out the easier way out. ;)
OpenStudy (saifoo.khan):
Got it. :D
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OpenStudy (saifoo.khan):
\[A = (L)^2\]Simplified version. ;)
OpenStudy (anonymous):
Okay, what is A and L? Are there specific numbers?
OpenStudy (anonymous):
I mean, what do they stand for?
OpenStudy (saifoo.khan):
P.S. sorry i forgot to mention them, A = area L = length.
Now, your A is turned down into 1/5. so make A = 1/5
\[\frac15 A = (L)^2\]
OpenStudy (saifoo.khan):
Now solve for L.
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OpenStudy (anonymous):
Would the answer be 25?
OpenStudy (saifoo.khan):
Nope.
OpenStudy (saifoo.khan):
take square roots on both sides,
\[\sqrt{\frac{1}{5}} = L\]
\[L = \frac{1}{\sqrt5}\]
\[L = \frac{\sqrt{5}}{5}\]
OpenStudy (anonymous):
.44?
OpenStudy (saifoo.khan):
Nope. that's the answer.
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OpenStudy (anonymous):
That is the answer?
OpenStudy (saifoo.khan):
i just read the question again and found out, i messed up the working. :(
I'm sorry.