Question

Find the distance between the given points.

C(7, 1) and D(4, -6)

Distance =

Answer 1

Do you know the distance formula?

Answer 2

The distance needs to fit in the two spaces under the radical. I don't know how to do it.

Answer 3

The information I gave for the question is what was given :/

Answer 4

\[d=\sqrt{(x _{2}-x _{1})^2+(y _{2}-y _{1})^2}\]

Answer 5

That's the distance formula. It says to put the x values of your ordered pairs in and the y values of your ordered pairs in. Then subtract them. Then square. Can you do that?

Answer 6

Your x values are 7 and 4

Answer 7

Your y values are 1 and -6

Answer 8

Honestly, it's all confusing :/ I am homeschooling and I was never taught this.

Ok so I then I would subtract them?

Answer 9

Well put the numbers in and see what happens. You can post your result and we'll see how it goes.

Answer 10

Ok, give me one second :)

Answer 11

Ok, I subtracted the 7 from 4 and multiplied 3X3=9 then I subtracted 1-neg6=-5 multiplied -5X5? and got 25. I did it wrong huh?

Answer 12

But 1-(-6) is 1+6 which is 7

Answer 13

ohh! ok so it would be 7X7=49 + the 9 = 58 as the answer?

Answer 14

So now we have:
\[d=\sqrt{9+49}=\sqrt{58}\]

Answer 15

Don't forget the radical.

Answer 16

Thank You for the help! I understand it now!

Answer 17

Do you know the Pythagorean theorem?

Answer 18

Because if you do, I want to show you something.

Answer 19

Once I see it, I will remember.

Answer 20

a^2+b^2=c^2. It's for right triangles.

Answer 21

Oh yes, I know those

Answer 22

Ok. Watch this.