Question

x^4 -81/x+3
Explain please!

Answer 1

\[x^4 -81 \]
There is some way you can expand this in the form of (x+3)

Answer 2

I just can't figure it out without getting the -81

Answer 3

I always get positive

Answer 4

factorise the numerator

\[\frac{(x^2 - 9)(x^+9)}{x+3}\]

(x^2 - 9) is the difference of 2 squares and can be factorised

\[\frac{(x -3)(x+3)(x^2 +9)}{(x+3)}\]

now you can eliminate the common factor ( x+3)

\[(x -3)(x^2 + 9)\]

Answer 5

oops 1s\[\frac{(x^2 -9)(x^2 +9)}{(x +3)}\]t factorisation should be