I don't know how to get the answer? Let alone do it:( Containing E(4, 3) and F(6, 1)
find linear equation?
Enter the equation of the line meeting the given conditions. Please put the equation in standard form.
Do you know Point slope form?
Yes, but I don't fully understand how to get the answer
Show me the formula, pls!
for point slope?
Yes, that's the most essential form for linear equation!
if I understand correctly it is y=1/2 * x/2 + something?
the formula, with slope m!
oh... um I don't know that one.
Would you look it up for the formula ( without the number)
look what up?
Point slope form for linear from where assign your homework?
I go to school online, and nothing was given about that. Just this equation as if they thought every student knew how to do it.
Yes, everybody are supposed to memorize it! y2 - y1 = m ( x2 - x1 )
So I would put the numbers in as the letters, and than get the answer that way?
First you find slope m = .... Plug the coordinate in:
how do I know which ones to use to find the slope?
Slope m = ( y2 - y1) / ( x2 - x1) You need TWO POINTS to make a line
So y2 would be 4 and y1 would be 6? and x2 would be 3 and x1 would be 1? or switch it around?
E(4, 3) and F(6, 1) x1 = 4, y1 = 3, x2 = 6, y2 = 1
x=2 / y=-2 ?
is that the answer? or do I divide 2 and -2?
I have 5spaces in the answer box...and I think I did something wrong
Oh...so it would be y=-2 as the answer?
x2-x1= 6-4=2
m=-1?
Yes, now plug into the linear equation y - y1 = m ( x - x1 )
ok I think IM over thinking this....what would I plug in? would it be -2=m2? but I can only Y & X in the answer?
You plug in ( 6,1) and m = -1
im lost? im sorry...I hope im not aggravating you
You really don't know point coordinate, don't you! x1 = 6, y1 = 1, m = -1 Now plug these into the formula: y - y1 = m ( x - x1 )
I know the coordinates to the point of finding where the points go on the graph, but I never was showed how to find them.
So. pls follow my instruction Point coordinate is x1 = 6, y1 = 1, m = -1 Now plug these into the formula: y - y1 = m ( x - x1 )
x=4, y=3= 1, m=1?
2=m-1
Either point, it works, m -1
y - y1 = y - 3 Can you do similarly with x
I don't know how to do that.
x - x1 = ...
3-1=2
x - 4
subtract 3 from 4?? =-1
y - 3 = - ( x - 4 )
y -3 = -x + 4 ->x = -x + 4 + 3 x = -x + 7
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