Question

factor 8x^(3) -1

Answer 1

Okay, well this is normally a very difficult thing to factor because it is a third degree polynomial and because there is a coefficient for x. However, if we can come up with one factor that works, then we can simply divide by that factor.

How can we get that first factor that will work? Well, hopefully there is some obvious x value that makes this 0. Can you come up with one?

Answer 2

One could also apply the difference of cubes formula:

\((a^3-b^3)=(a-b)(a^2+2ab+b^2)\)

This is considered the "mechanical" process.

Answer 3

That awkward moment when the person ignores your reply and bumps the question.

Answer 4

(a^3-b^3)=(a-b)(a^2+ab+b^2)

Answer 5

I agree, Math. I believe they were awaiting an answer; rather than help.

Answer 6

Yeahwell.

Answer 7

\(8x^3 -1= (2x)^3-(1)^3 = (2x-1)(4x^2+2x+1) \)

Using \( (a^3-b^3)=(a-b)(a^2+ab+b^2) \)

Answer 8

Yes, use the difference of two cubes formula.

Answer 9

Limitless-> 2 votes; wrong answer.

Answer 10

Ffm, I'm not sure why I got double voted, either. Am I just pleasant a figure?

Answer 11

You were just fast :)

Answer 12

FFM -> 0 votes; direct solution given.

Answer 13

*with explanation.