Find the exact value of the radical expression in simplest form.

Question

anonymous · Answer

$$2\sqrt{7x}+\sqrt{7x} -3\sqrt{7x} ^-7$$

anonymous · Answer

Dont just want the answer. I need someone to help me understand it. please :(

campbell_st · Answer

not sure what the last term is ... perhaps -7

but look at the terms involving

$$\sqrt{7x}$$

there is 2 + 1 -3

$$(2 + 1 - 3)\sqrt{7x} = 0$$

its just like saying 2x + x -3x = 0

anonymous · Answer

^-7

campbell_st · Answer

ok so the last term is $$3\sqrt{7x^7}$$

campbell_st · Answer

rewrite the last term

$$3\sqrt{7x \times x^6} =====> 3\sqrt{7x}\times \sqrt{x^6} = 3x^3\sqrt{7x}$$

so the expression is 

$$2\sqrt{7x} + \sqrt{7x} - 3x^3\sqrt{7x}=====> (2 + 1 - 3x^3)\sqrt{7x} ==>(3-3x^2)\sqrt{7x}$$