Question

Find the exact value of the radical expression in simplest form.

Answer 1

\[2\sqrt{7x}+\sqrt{7x} -3\sqrt{7x} ^-7\]

Answer 2

Dont just want the answer. I need someone to help me understand it. please :(

Answer 3

not sure what the last term is ... perhaps -7

but look at the terms involving

\[\sqrt{7x}\]

there is 2 + 1 -3

\[(2 + 1 - 3)\sqrt{7x} = 0\]

its just like saying 2x + x -3x = 0

Answer 4

^-7

Answer 5

ok so the last term is \[3\sqrt{7x^7}\]

Answer 6

rewrite the last term

\[3\sqrt{7x \times x^6} =====> 3\sqrt{7x}\times \sqrt{x^6} = 3x^3\sqrt{7x}\]

so the expression is

\[2\sqrt{7x} + \sqrt{7x} - 3x^3\sqrt{7x}=====> (2 + 1 - 3x^3)\sqrt{7x} ==>(3-3x^2)\sqrt{7x}\]