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OpenStudy (wolfboy):
The number of permutations of two items from a data set is
always two times the number of combinations when taking two
objects at a time from the same data set. .
OpenStudy (anonymous):
D: I dunno this yet. Sorry.
OpenStudy (wolfboy):
I know its true but i cant remember why.
OpenStudy (anonymous):
Master!
OpenStudy (wolfboy):
?
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OpenStudy (saifoo.khan):
@dpaInc THE BOSS.
OpenStudy (wolfboy):
?
OpenStudy (wolfboy):
soooooooo no help?
OpenStudy (saifoo.khan):
@dpaInc HELPP!!!
OpenStudy (wolfboy):
no a pickle
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OpenStudy (saifoo.khan):
Dpanic likes tarts.
OpenStudy (wolfboy):
hmmmm
OpenStudy (anonymous):
Combinations: n! / r!*(n-r)! r is number of things you're choosing and n is total possible number of things to choose from. And of course...order doesn't matter
Permutation: n! / (n-r)! Order does matter...you have less options to choose after each iteration
OpenStudy (wolfboy):
thank you and can you help with one more?
OpenStudy (anonymous):
So just throw in your n and r and walk through it
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OpenStudy (wolfboy):
No you answered the question bu i have one more
OpenStudy (wolfboy):
*but
OpenStudy (wolfboy):
o wait nvm
OpenStudy (wolfboy):
Thx
OpenStudy (anonymous):
no problem, this is my 1st time on here. Looks like a good site
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