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OpenStudy (anonymous):
Use properties of logarithms to expand the loarithmic expressions as much as possile.
log_4 7-2
1) 7log4 4
2) 4log4 7
3) -4log4 7
4) -16log 7
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OpenStudy (saifoo.khan):
7-2?
OpenStudy (anonymous):
7-^2
OpenStudy (saifoo.khan):
\[\log_4 7^{-2} \to \log_4 (\frac{1}{49})\to \frac{\log \frac{1}{49}}{\log 4}\]
OpenStudy (saifoo.khan):
are the options you wrote correct? @Audrae_World
OpenStudy (anonymous):
Yes, that's what my book says
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OpenStudy (anonymous):
Isn't it \[\log_{4} 1 - \log_{4} 7^{2}\]
OpenStudy (anonymous):
Its expand not solve @saifoo.khan
OpenStudy (saifoo.khan):
Yes! im stuck. :/
OpenStudy (anonymous):
@Audrae_World : Is it \[\log_{4} 7^2\]
OpenStudy (anonymous):
That's the closest I've seen so far, but the one of answer choices says: 4log_4 7^2
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OpenStudy (anonymous):
Are you sure the problem is \[\log_{4} 7^{-2}\] ?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Oh. I got it. Hold on.
OpenStudy (anonymous):
\[\log_{4}7^{-2} = -2(\log_{4}7) = -2(\log_{7}7/\log_{7}4) = -2(1/\log_{7}2^{2})\]
\[-2(\log_{7}2^{-2}) = -2 * -2(\log_{7}2) = 4\log_{7}2\]
OpenStudy (anonymous):
Wait. Darn it...
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OpenStudy (anonymous):
LOL @Calcmathlete :whats that !??
OpenStudy (anonymous):
lol. I got so close!!! But then I realized that it isn't one of the answers...
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