https://www.connexus.com/content/media/478541-3282011-20545-PM-1388392569.jpg

plz solve dis 4 me, thx :)

Question

https://www.connexus.com/content/media/478541-3282011-20545-PM-1388392569.jpg

plz solve dis 4 me, thx :)

anonymous · Answer

$$
\frac{-14x^3}{x^3-5x^4}
$$

anonymous · Answer

That cannot be solved, but it can be simplified, are you trying to simplify it? You can pull an $x^3$ out of the denominator and cancel it with the $x^3$ in the numerator.

anonymous · Answer

yeah, dat is wat im trying 2 do..lol..srry

anonymous · Answer

so, what is my final answer...i have trouble wit these kind of things

anonymous · Answer

Well, what do you get when you factor an $x^3$ out of the denominator?

anonymous · Answer

they cancle out?

compassionate · Answer

$$-14^2/x^2 - 5x^4  $$

Remember that when you have powers in the denominator and numerator, they will subtract from each other in order to simplify. In this equation the dominate power x-to the fourth remains. The equation simplifies to:

$$14/1-5x$$  

The equation above reads: Negative 14 over one-minus five- times x.