Question

Show by using slope that the figure with vertices A(-5, -2), B(-4, 2), C(4, 5), and D(3, 1) is a parallelogram.

Slope of AB = 4

Slope of CD = 1/4

Slope of BC = 0

Slope of AD =-8

Answer 1

which of my answers are wrong??

Answer 2

i know i have som wrong but i dont know which

Answer 3

All

Answer 4

it says partial credit in my answers..

Answer 5

*meaning i got some right

Answer 6

ab is correct.

Answer 7

b is wrong.

Answer 8

how?

Answer 9

I mean, BC x(

Answer 10

BC is 3/8 there! No more confusion, lol

Answer 11

BC is wrong too

Answer 12

lol

Answer 13

i mean @seashell was wrong @zepp is correct.
Please give him a medal @seashell

Answer 14

CD is wrong too, should be 4

Answer 15

@zepp STOP GIVING DIRECT ANSWERS MAN

Answer 16

can u explain how?

Answer 17

Thought that was multiple choice! D:

Okay, there: \(\huge m = \frac{y_2 -y_1}{x^2-x^1}\)

Answer 18

This is the formula to find the slope, let's find the slope of BC.
B(-4, 2), C(4, 5)

\(\huge m=\frac{y_2-y_1}{x^2-x^1}\)

Plug stuffs in

\(\huge m=\frac{(5)-(2)}{(4)-(-4)}=\frac{3}{8}\)

Answer 19

thank you!!:D appreciate it.. i would become your fan again :)

Answer 20

Haha, you are welcome :)

Answer 21

Now to show that this thing is a parallelogram, verify that the 'supposed-to-be-parallel-sides' has the same slope (there's two pairs), good luck! :]

Answer 22

ok!!:D