Question

Solve for x

3sinx - 2cosx^2x = 0

Answer 1

3sinx -2cos²x + 2sin²x = 0
3sinx -2+4sin ²x=0
then factorise them

Answer 2

@sparkly16 Sorry to ask, but is this your question?
\[3sinx - 2cos^2x = 0\]

Answer 3

3sinx−2cos² 2x=0

Answer 4

opps

Answer 5

3sinx−2cos 2x=0 tis one

Answer 6

yes

Answer 7

Once again... Is it (i) or (ii)?
\[(i)3sinx - 2cos^2x = 0\]\[(ii)3sinx - 2cos2x = 0\]

Answer 8

its (i)

Answer 9

oh so it is
3six x -2 +2 sin²x then sin x =0.5?

Answer 10

Use the identity \[sin^2x+cos^2x=1\]
\[3sinx - 2cos^2x = 0\]\[3sinx - 2(1-sin^2x) = 0\]\[3sinx - 2 + 2sin^2x = 0\]\[2sin^2x + 3sinx - 2 = 0\]\[(2sinx-1)(sinx +2)=0\]\[2sin^2x + 3sinx - 2 = 0\]\[(2sinx-1)=0 \ or \ (sinx +2)=0\]\[sinx=\frac{1}{2} \ or \ sinx = -2 (rejected)\]So, sinx = 0.5
Take arc sin to find the value of x, can you?

Answer 11

thank you so much! :)

Answer 12

Welcome :)