Question

Please help me out!!? http://i49.tinypic.com/1q0nec.png I need this asap!!! :(

Answer 1

:S

Answer 2

How I post an image?

Answer 3

go to tinypic.com and upload it then link the direct link here. :) and if you're going to type on the post also copy/paste the text here too.

Answer 4

@jpsmarinho

Answer 5

:x

Answer 6

:)

Answer 7

ok proving similarlity

(a) triangle TAN and TRI

Angle T common to both triangles
Angle TAN = angle TRI corresponding angles in parallel lines AN// RI

therefore triangle TAN is similar to triangle TRI by angle angle test

NB.... Angle Angle test only requires 2 congruent angles as by angle sum of a triangles the 3rd in each triangle will be equal

(b) TAN is a contraction of TRI ( smaller)

scaling factor look at corresponding sides

then the ratio AN: RI = 6: 8 or 3:4 triangle TAN is 3/4 of TRI

(c) find AR use the ratio of sides and let TR = AT + x

\[\frac{RI}{AN} = \frac{TR}{TA} =====> \frac{8}{6} = \frac{3.3 + x}{3.3}\]

then \[3.3 + x = \frac{3.3 \times8}{6}====== x = \frac{3.3 \times 8}{6} - 3.3\]

x or AR = 1.1 units

(d) I have no idea of the Side Splitting Theorem

by my best guess is use the ratios

\[\frac{NI}{AR} = \frac{TN}{TA} =====> \frac{1.6}{1.1} = \frac{TN}{3.3}\]

TN = 4.8

(d) the linear ratios is tri TAN: tri TRI is 3:4 for the areas square each

3^2: 4^2

9: 16

then the area of triangle TAN is 9/16 of triangle TRI

hope this helps

Answer 8

Thanks a ton! That was very helpful and informative. Thank you for taking your time to answer it all. My friend didn't understand I didn't know how to do it. We both thank you a ton! :)