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please solve it \[\int\limits_{0}^{\pi}\sin (x) \cos(nx) dx\]
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answer is \[-2\div (n^{2}-1) \] ,for n=even and 0 for n= odd
use integration by parts twice
alternatively use this trig identity\[\sin (u) \cos (v)=\frac 12\left[ \sin(u+v)+\sin(u-v)\right]\] \[\sin (x) \cos (nx)=\frac 12\left[ \sin((n+1)x)+\sin((1-n)x)\right]\]
good
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