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differentiate using quotient rule (x-1)(x+2)/x
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\[ \frac{(x-1)(x+2)}{x}=\frac{x^2+x-2}{x}\\ \left(\frac f g \right)'=\frac{gf'-fg'}{g^2}\\ f=x^2+x-2,\ g=x\\ f'=2x+1,\ g'=1 \]
You can take it from there?
yh it will be x(2x+1)-(x^2+x-2)1/x^2
s this ryt nbouscal
2x^2+x-x^2-x+2/x^2
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Can you simplify that further?
yh will it be \[x^2+ 2/x^2\]
Yeah, which you can simplify further to \(1+\dfrac{2}{x^2}\)
and this = 2 am i ryt ?
k s this the final answer
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yes
thk u so mch
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