Question

using quotient rule differentiate y=cosx/sinx

Answer 1

We've done a couple of these, so you should know the rule by now. Which step are you getting stuck at?

Answer 2

the step hw to get the formula

Answer 3

What do you mean how to get the formula? I've given you the formula for the quotient rule twice.
(gf'-fg')/g^2

Answer 4

will it be -sinx/cosx ?

Answer 5

No, it won't. How did you get that?

Answer 6

i jst wrote the values of cosx and sinx

Answer 7

You can't just derive the top and derive the bottom, you have to use the quotient rule. It's the exact same method as the last two quotient rule problems that I have walked you through. Find f, g, f', g', and plug them into the quotient rule formula.

Answer 8

that is where am havin problems
hom to find the f g f' g'

Answer 9

f is the numerator, g is the denominator, and you derive them to find f' and g'

Answer 10

how do i derive to get f' g' since f=cosx and g=sinx

Answer 11

I told you what the derivatives of those were two problems ago, when we were deriving tangent of x. I told you that you need to memorize them. Memorize them.

Answer 12

are they -sinx and cosx

Answer 13

will it be (sinx(-sinx)-cosx(cosx))/sin^2x
nbouscal is this right?

Answer 14

ya u r right.

Answer 15

simplify this to get the final answer.