If A,B subsets of R is bounded, then show that AUB also bounded.
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OpenStudy (experimentx):
let \( a_1 \) be upper bound of A and \( b_0 \) be upper bound for B,
if \( a_1 > b_1 \) then \( a_1 \) is bound for B also, so \( a_1 \) is bound for AUB
if \( b_1 > a_1 \) same case
do same for lower bounds
OpenStudy (experimentx):
*similar case
OpenStudy (anonymous):
why your answer appears [Math Processing Error].
But i know what is it..let x be upper bound of A and y be upper bound for B..like this?
OpenStudy (experimentx):
yes
OpenStudy (anonymous):
ok, now it can read..thanks
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OpenStudy (anonymous):
A is bounded means that there is K>0
\[
a\in A \text { implies } |a| \le K
\]
B is bounded means that there is H>0
\[
b\in B \text { implies } |b| \le H
\]
Let G= K + H
\[
c\in A \cup B \text { implies } |c| \le G
\]
OpenStudy (experimentx):
kinda remembered that ... ty prof!!
OpenStudy (anonymous):
yw
OpenStudy (anonymous):
You can of course also take G=Sup{H,K}.
OpenStudy (anonymous):
thanks guys..
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