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Mathematics 20 Online
OpenStudy (anonymous):

If A,B subsets of R is bounded, then show that AUB also bounded.

OpenStudy (experimentx):

let \( a_1 \) be upper bound of A and \( b_0 \) be upper bound for B, if \( a_1 > b_1 \) then \( a_1 \) is bound for B also, so \( a_1 \) is bound for AUB if \( b_1 > a_1 \) same case do same for lower bounds

OpenStudy (experimentx):

*similar case

OpenStudy (anonymous):

why your answer appears [Math Processing Error]. But i know what is it..let x be upper bound of A and y be upper bound for B..like this?

OpenStudy (experimentx):

yes

OpenStudy (anonymous):

ok, now it can read..thanks

OpenStudy (anonymous):

A is bounded means that there is K>0 \[ a\in A \text { implies } |a| \le K \] B is bounded means that there is H>0 \[ b\in B \text { implies } |b| \le H \] Let G= K + H \[ c\in A \cup B \text { implies } |c| \le G \]

OpenStudy (experimentx):

kinda remembered that ... ty prof!!

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

You can of course also take G=Sup{H,K}.

OpenStudy (anonymous):

thanks guys..

OpenStudy (anonymous):

yw

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