Find all the possible values between 0 and ten that will satisfy.... x≅1(mod 2)???? I answered 3, 5, 7 and 9.
I'm just curious, but why didn't you choose 1?
That is actually why I posted the question because I couldn't figure out why 1 satisfied the equation.
I didn't understand the question :/
\(\mathbb{mod}(x,y)\) Is one value missing?
what do you mean?
What is \(1(mod2)\)?
basically I was asked to find all of the values of x that are CONGRUENT to 1(mod 2)
Yes, I know, but what is \(1(\mathbf{mod} 2)\)?
Modular arithmetic. 1(mod2), divide a number by 2 and get a remainder of 1.
Do you mean that we have to find the values of x where \(mod(x,2) = 1\)? I think that's your question.
Yes, I know it. And indeed, that's you question.
\(\Large \color{Black}{\Rightarrow x \epsilon 1,3,5,7,9 }\)
what notation are you using?
\(\large \color{Black}{\Rightarrow x \text{ } \epsilon \text{ } \mathfrak{ odd } }\)
How did you get 1?
Yeah I'm sorry, I couldn't understand the notation.
0 divided by 2 leaves remainder 1 and quotient 0.
How did you solve this problem may I ask?
And you should've used \(\equiv\) instead of \(\cong\). Hope this helped.
Well you check all the values that give the remainder as 1.
0 divided by 2 leaves remainder 1 and quotient 0!!!, what type of maths of this?
Lol it's the same thing.
lol that has really confused me.
You have to check the numbers that leave the remainder as 1, and 0/2 leaves the remainder as 1. agree?
my calculator does not agree no.
Oopsie. I got confused lol.
I meant 1/2
I am quite confused about how 1 can be a solution.
All odd numbers are solutions.
what about about the whole remainder of 1 business?
That is the question.
x = 1(mod 2) means that when x is divided by 2, it leaves the remainder of 1.
and 1/2=1/2, so I cannot understand now 1 can be a solution.
All the numbers that can be expressed as \(2\mathbb{Z} + 1\) are solutions here.
\(\mathbb{Z}\) can be 0 here. So, 2(0) + 1 = 1
Divide 1 and 2, it'll leave a remainder of 1.
could how show me please?
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