Question

How to solve it Lim {(x^8 + x^4 )^(1/2)}/x^2 when x goes to 0. Is much hard with L'Hôspital , I think.

Answer 1

factor out the top

Answer 2

(x^8 + x^4 )^(1/2)

= [x^4(x^4+1)]^(1/2)

= x^2(x^4+1)^(1/2)

Answer 3

as such, we have a removable discontinuity and we are left with:

sqrt(x^4+1); at x=0

Answer 4

O_O thank God, you get it! Thanks!!