Boy A throws a ball vertically up with speed u . Boy b on the top catches it and throws down with u to A . the times for the two travels (ascent : decent) are in ratio 2:1 The height of the tower is ?

Question

anonymous · Answer

I think it's quite easy question, you must be able to solve that. Try to do this yourself.

anonymous · Answer

is that a maximum height...

anonymous · Answer

@ArchiePhysics

anonymous · Answer

First you need to find the time of ascent
using
v =vi-gt

anonymous · Answer

i got u=10t

anonymous · Answer

@ArchiePhysics .............

anonymous · Answer

h=12 u^2/25g 
is this correct answer?

anonymous · Answer

@open_study1

anonymous · Answer

yes i have an option like that

anonymous · Answer

but how u got it???

ajprincess · Answer

vat r ur other options?

anonymous · Answer

I have used standard formulas
h(t) = hi+vit+at^2/2
v = vi+at
and given ratio
t1/t2=2

anonymous · Answer

Try to solve it yourself. It is easy.

anonymous · Answer

6u^2/25g      12u^2/25g     18u^2/25g    24u^2/25g

anonymous · Answer

@ajprincess  these are my options

anonymous · Answer

i got u=10t @ArchiePhysics  is this correct

anonymous · Answer

so ......wat is the real answer??

anonymous · Answer

@ArchiePhysics

anonymous · Answer

can u show ur method @ajprincess

ajprincess · Answer

|dw:1338655312620:dw|
used these three eqns and found it.