Question

Paraobla Help
I have a parabola plotted on a graph, but I do not understand how to put it into an equation or find its vertex. I have the two points it starts and stops on tho. (0,0) and (10,0)

Answer 1

the parabola can open upwards or downwards... which way does it open?

Answer 2

it goes up

Answer 3

what do you mean?

Answer 4

(0,0) and (10,0)

These things looks like the x-intercepts

Answer 5

Give us another random point on the parabola, and we can solve it :]

Answer 6

ohh okay holdon

Answer 7

Theres a picture of it. (5,2) is where it goes to about

Answer 8

Vertex is approximately at (5.5, 3)

Answer 9

x-intercepts at (1,0) and (10,0)

Answer 10

By using the root form (or whatever this is) factored form I believe;

\(\large y=a(x-z_1)(x-z_2)\)

Where a is a constant that determine the fatness and direction of the parabola
z1 and z2 are x-intercepts (or roots)

Answer 11

Let (x,y) be the vertex;
(5.5, 3)

Then

\(\large y = a(x-z_1)(x-z_2)\)

Plug in stuffs

\(\large 3 = a(5.5-1)(5.5-10)\)

Find a

\(\large 3 = a(4.5)(-4.5)\)
\(\large a = -\frac{4}{27}\)

Answer 12

The equation of this parabola would be \(\large y=-\frac{4}{27}(x-1)(x-10)\)

Answer 13

i need to use this formula for the equation think of a quadratic equation in general form, y = a(x - h)2 + k

Answer 14

what is a? and what are h and k?

Answer 15

(h,k) are the vertex

Answer 16

What's your vertex?

Answer 17

Vertex is approximately at (5.5, 3)

Answer 18

What's a?

Answer 19

I dont know

Answer 20

http://puu.sh/yoeQ

I'm a little bit angry about the fact that you didn't even take the time to read my explanations :|