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Find the zeros of the function g(x) = 2x^4+ 2x^3− 6x^2− 2x + 4 .
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\[x-1\] is a factor beause \[f(1)=0\] and also if we try \[x=-1\] it works so we have two other factors to get x=1 twice x=-1 x=-2
Hi deejay :) set g(x)=0 and solve it for x. You will get 4 answers as x has maximum 4 exponent
those were the only 3 i knew how to get. . but my answer was wrong.
ok the equation is \[y=2(x-1)(x-1)(x+1)(x+2)\] roots \[x=-2,x=-1,x=1\]
since x=1 appears twice
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