Question

Use synthetic division and the solution x = 9 −√7
to find the zeros of x^3− 14x^2+ 2x + 296 = 0 .

Answer 1

x^3 -14x^2 +2x +296 / x -(9 + sqrt7) = x^2 +(-5+sqrt7)x +(-36+4sqrt7)
x^3 -(9+sqrt7)x^2
-----------------
0 (-5+sqrt7)x^2 +2x
(-5+sqrt7)x^2 -(9+sqrt7)(-5+sqrt7)x
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0 (2+(-45+9sqrt7 -5sqrt7 +7))x +296

0 (-36 +4sqrt7)x +296
(-36+4sqrt7)x - (-4(9-sqrt7)(9+sqrt7))
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0 296 +(-4(81-7))

0 296 - (4*74)
0 296 - 296
0 0

Answer 2

so from this resulted that x=9-sqrt7 is solution of this ecuation

Answer 3

ok ?

Answer 4

k

Answer 5

for you get the second and 3rd root of this ecuation you need to solve this quadratic ecuation what we have get divided this equation by x-9+sqrt7

Answer 6

ok ?

Answer 7

what ?