Question

Seriously the hardest question ever!
Page 4 of this document PLEASE HELP
http://dl.dropbox.com/u/66795014/66518010-IA-2012-2013.pdf

Answer 1

No one could answer ha ha!

Answer 2

first part is oke right?

Answer 3

\[y_1=(x-a)^2+b^2\] vertex is \((a,b)\) and zeros are
\[(x-a)^2+b^2=0\]
\[(x-a)^2=-b^2\]
\[x-a=\pm\sqrt{-b^2}=\pm\sqrt{b^2}\sqrt{-1}=\pm bi\]
\[x=a\pm bi\]

Answer 4

sorry vertex is \((a,b^2)\)

Answer 5

since vertex is \((a,b^2)\) that line labeled \(y_m\) is actually \(y_m=b^2\)

Answer 6

Yeah, I am good with taht

Answer 7

ok then the "various values" part you just pick numbers right?

Answer 8

yeah kinda

Answer 9

I dont know where ur goin with this?

Answer 10

and for the last part, you have another parabola with the same vertex, but facing down

Answer 11

Yeah
opposite concavity

Answer 12

so it is
\[y_2=-(x-a)^2+b^2\]

Answer 13

yep thats reasonable

Answer 14

zeros are easy enough to find right?

Answer 15

can you help me with that a little?

Answer 16

I just feel something is going to go bad with it

Answer 17

\[-(x-a)^2+b^2=0\]
\[-(x-a)^2=-b^2\]
\[(x-a)^2=b^2\]
\[x-a=\pm\sqrt{b^2}\]
\[x-a=\pm b\]
\[x=a\pm b\]

Answer 18

ok thats good now thanks

Answer 19

so for the rest

Answer 20

i am not sure what that \(y_m\) is doing there, i guess you can replace \(b^2\) by \(y_m\) but that seems kind of silly

Answer 21

these questions are just vague

Answer 22

Ok then what am i going to do it says use several values to produce pairs of functions

Answer 23

it says express \(y_2\) in terms of \(y_1\) and \(y_m\) so i guess you could say
\[y_2=-y_1+2y_m\] or some such silliness

Answer 24

yeah
thats cool it works

Answer 25

ok good luck!

Answer 26

Can you help me with the part that says, use several values to produce pairs of functions

Answer 27

Did u leave?

Answer 28

pick numbers

Answer 29

\[y=(x-2)^2+9\] for example

Answer 30

o ok, Now it says the graph
one the diagram with proper labeling

Answer 31

zeros are
\[2\pm3i\]

Answer 32

yep that works

Answer 33

make your life easy and pick things like \(a=1, a=2, a=3\) a likewise for \(b\)

Answer 34

Ok and how do i use the diagram with proper labeling?