Question

Plzzz can someone help me? Thanx.:)

Answer 1

I understand the q and I know it is true I jsut dont know how to prove it. maybe something about f(x)

and shifting it f(x-a)+b :)

Answer 2

sorry... i don' have open office or word... how 'bout a pdf?

Answer 3

if you have hotmail it has a free viewer :) via skydrive

Answer 4

jst a moment let me convert it.

Answer 5

it says Advance.. i hope it's not too advanced otherwise you're doing this for nothing.. :)

Answer 6

@dpaInc hw abt a screenshot? I hav posted a screenshot.

Answer 7

hmmm.. yep.. too advanced for me... sorry.... :(

Answer 8

it's k. Thanxx a lot for tryng to help me. :)

Answer 9

when ur done with this i can help with the times table... :)

Answer 10

:)

Answer 11

Thanxx a lot @timo86m for the suggestion.

Answer 12

r1,r2,r3,r4 are vectors
a1r1 + a2r2 + a3r3 + a4r4 =0
now r1 is position vector w.r.t O,,for any other point O' ,,vector is r1 - OO'
and the others become r2 - OO' , r3 -OO', r4-OO'
we need to find a1(r1 - OO') + a2(r2-OO') + a3(r3-OO') + a4(r4 -OO')
=> ( 0 ) - OO' ( a1 + a2 +a3 +a4)
clearly is becomes 0 for a1 +a2 + a3 + a4 =0
hence proved..

Answer 13

if u dnt mind can u please tell me hw u got r1-OO'? That part is nt clear to me.

Answer 14

we can see easily that
r1 = OO' + (required vector)
thus req. vector is r1 - OO'