Question

(27x^6)^2/3

Answer 1

\[(27x ^{6})^{2/3}\]

Answer 2

distribute the exponents again...

(27^2/3)(x^6*2/3)

Answer 3

\[\large (27^{2/3}) \times (x^{6 \times 2/3}\]

Answer 4

Would it be the same if I have a fraction?
My next problem looks like this: \[\left(\begin{matrix}16 \\81\end{matrix}\right)^{1/4} \left(\begin{matrix}125 \\ 8\end{matrix}\right)^{-2/3}\]

Answer 5

\[\large (\frac{a}{b})^x = \frac{a^x}{b^x}\] did that answer your question??

Answer 6

For the one before this one I got up to\[(27^{2/3})(x ^{12/3})\] when I solve that I get 27^8 but the book says the answer is 9x^4, how?

Answer 7

you know that x^12/3 is x^4 right?

Answer 8

because 12/3 is 4

Answer 9

Yes, but dont I have to add it to 27^2/3

Answer 10

to the 2/3 part

Answer 11

you only add when the same base

Answer 12

\[a^x a^y = a^{x+y}\]

Answer 13

\[a^xb^y = a^xb^y\] no change

Answer 14

another thing... \[\large x^{a/b} = \sqrt[b]{x^a}\] therefore \[\large 27^{2/3} = (\sqrt[3]{27})^2\]

Answer 15

are these making sense?

Answer 16

yes! wow, i cant believe i forgot algebra so easily. Sorry I havent taken algebra for like 10 years :) Thanks again!

Answer 17

you're welcome ^_^