An elevator is going down with a constant acceleration. A coin is dropped from a point 1.8m above the floor takes 1 second to reach the floor The magnitude of the acceleration of the elevator is ? (g=10m/s^)

Question

apoorvk · Answer

so, the net acceleration of the coin g minus the acc. of the lift.

use this funda.

anonymous · Answer

Relative Acceleration = g-a

anonymous · Answer

Exactly. Now that you are in the lift. It's a normal question again.
s = 1.8
t = 1s
a = g - x ( x is acceleration of lift)
s = 1/2at^2.

anonymous · Answer

ok the answer is 6.4m/s^2 is it @siddhantsharan

anonymous · Answer

Yeah. I think so.

anonymous · Answer

Thxxx

aravindg · Answer

exactlly the question talks of a non-inertial system, only thing u have to do is to make it to a inertial system by using a pseudo force ,the rest of ur work is simply applying newttons eqns !!