Two cards are drawn, without being replaced from a deck of 52 cards. Find the probability of selecting a king and a queen.

Question

parthkohli · Answer

$ \color{Black}{\Rightarrow P(\mathbb{KING}) \times P(\mathbb{QUEEN}) }$

parthkohli · Answer

$ \color{Black}{\Rightarrow \Large {4 \over 52} \times {4 \over 52} }$

$ \color{Black}{\Rightarrow \Large {1 \over 13} \times {1 \over 13} }$

$ \color{Black}{\Rightarrow \Large {1 \over 13^2} }$

anonymous · Answer

I don't know what you did

parthkohli · Answer

What is the probability of selecting a king?

anonymous · Answer

of selecting a king and a queen

parthkohli · Answer

No, first tell me what is the probability of selecting a king if you pick on card?

parthkohli · Answer

one*

anonymous · Answer

idk...

parthkohli · Answer

There are 4 kings....there are total 52. P(Event) = Possible number of outcomes/Total number of outcomes.

unklerhaukus · Answer

there are thirteen cards from each suit in the deck

mertsj · Answer

4/52 times 4/51

parthkohli · Answer

Oh I see...seems like I missed the part "not being replaced"

phi · Answer

4/52 * 4/51 is prob of K followed by Q
now what about Q followed by K?