Question

A particle along a straight line with uniform acceleration covers distance AB= 8m and BC=18m in one second each . The speed of the paticle at point B is?

Answer 1

The answer should be 13 m/s

Answer 2

Use s=ut+1/2at^2

Answer 3

First for AB and then for AC. Solve them to find u and a. Then using these infos find the velocity.

Answer 4

@ajprincess both acceleration and u is not given so how???

Answer 5

u hav to find them.

Answer 6

Let me try and will inform u ....

Answer 7

ha k.:)

Answer 8

@ajprincess After solving i got a=10m/s^2

Answer 9

that's right. nw find u.

Answer 10

yes u=3m/s

Answer 11

so 13m/s

Answer 12

thxxx for helping

Answer 13

yw. well done.:)

Answer 14

\[s=ut+1/2 at ^{2}\]
\[8=u _{1}+a/2--- eq(1)\]
\[18=u _{2}+a/2---eq(2)\]
dividing eq(1) and eq(2)
\[\left[ (8-u _{1})/18-u _{2} \right]=1\]
\[8-u _{1}=18-u _{2}\]
\[u _{2}-u _{1}=10\]
as\[u _{1}=3\]
\[u _{2}=13 m/s\]