Question

If in one of the rope system on one side is 50.20 kg & other side is 49 Kg , also system friction force is 1kg then 50.20 kg reaches approx 11 m/s after 1 sec. Thereafter if i add the weight of 1 kg on 49kg side mass then what would be the velocties after 2 sec

Answer 1

From reading I assume the friction is kinetic and is 1 Newtons [(kg m)/sec^2) not kilogram. Also if you are giving masses and not weights the coefficient of kinetic friction \[\upsilon = .001\]however if you are giving weight \[\upsilon = .01\] you get this using \[\upsilon=f _{k}/N\] where\[N=m _{1}+m _{2}\] once you have coefficient of kinetic friction you first solve for the new force of friction by adding 2kg then use that number with the coefficient of kinetic friction in \[a=f _{k}/m\]and then use the new acceleration to find the velocity after 2 sec.