F=Dp/dt what does the d stand for??
differential, infinitesimal increment or linear part of the function. Depends on situation
please explain this to me, ive never taken calculus
in this case the formula is for the change of a momentum of a body, no?
yes!
d stands for small, very small increment of a cuantity: \[p _{2}-p _{1}=dp\] when this difference is as small as one whants it to be
so what this formula states is: force aplied to a rigid body is a instantanious (time lap is also very small) change of it's momentum
Or it says "rate of change of linear momentum defines force"
\[F=\frac{\text dp}{\text dt}\] \(\frac{\text dp}{\text dt} \) is the small change in momentum time changes by a small amount, think of it as the tangent to a curve \(p(t\)) we have to use infinitesimals because the force will change with time
could u just write it as F=p/t ???
this would be average force over a period of time.
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