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Physics 19 Online
OpenStudy (anonymous):

F=Dp/dt what does the d stand for??

OpenStudy (anonymous):

differential, infinitesimal increment or linear part of the function. Depends on situation

OpenStudy (anonymous):

please explain this to me, ive never taken calculus

OpenStudy (anonymous):

in this case the formula is for the change of a momentum of a body, no?

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

d stands for small, very small increment of a cuantity: \[p _{2}-p _{1}=dp\] when this difference is as small as one whants it to be

OpenStudy (anonymous):

so what this formula states is: force aplied to a rigid body is a instantanious (time lap is also very small) change of it's momentum

OpenStudy (anonymous):

Or it says "rate of change of linear momentum defines force"

OpenStudy (unklerhaukus):

\[F=\frac{\text dp}{\text dt}\] \(\frac{\text dp}{\text dt} \) is the small change in momentum time changes by a small amount, think of it as the tangent to a curve \(p(t\)) we have to use infinitesimals because the force will change with time

OpenStudy (anonymous):

could u just write it as F=p/t ???

OpenStudy (anonymous):

this would be average force over a period of time.

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