Question

Solve equation (2+2i) z^3=-1, where z is complex number.

Answer 1

solve for ? z ?

Answer 2

yes

Answer 3

hmmn,,make thise substitutions:
1+i = sqrt(2)e^(ipi/4)
solve for z ..was it helpful ?

Answer 4

wel... not really

Answer 5

it only complicates things

Answer 6

hmmn
we have this
2(1+i) z^3 = -1
=>2(_/2)e^(ipi/4) z^3 =-1
=>z= [-1/2(_/2)e^(ipi/4)]^1/3
just simplify..
note that e^(ipi/12) = cos(pi/12) + isin(pi/12)