Question

a quadrilateral has no pairs of parallel sides which name best describes the figure.

Answer 1

Depending on your book, the answer is either trapezoid or trapezium. This is because the definition of both trapezoid or trapezium vary throughout the world.

Answer 2

Eg: In the US, a trapezoid is a quadrilateral with EXACTLY one pair of parallel sides

Answer 3

i was going to go with a trapezoid but i wasn't sure?

Answer 4

and in the US, a trapezium is a quadrilateral with NO parallel sides

Answer 5

So because I'm guessing you're in the US (if not, my apologies), your answer will most likely be trapezium.

Answer 6

hey i got another question

Answer 7

what's that?

Answer 8

3x-14=x+30
those are the answers they give me.
22
76
16
30

Answer 9

Any ideas where to start?

Answer 10

hell no lol

Answer 11

we want to get x all by itself

So we want x on one side and everything else on the other

Answer 12

So start with adding 14 to both sides

3x-14=x+30

3x-14+14=x+30+14

3x = x+44

Answer 13

Then subtract x from both sides

3x = x+44

3x-x = x+44-x

2x = 44

Answer 14

Finally divide both sides by 2 to isolate x

2x = 44

2x/2 = 44/2

x = 22

Answer 15

omg thank youu!!!!!!

Answer 16

you're welcome

Answer 17

a square ABCD has the vertices A(n,n) B(n,-n) C(-n,-n) and D(-n,n) which is in quadrant three

Answer 18

Does it say if n is positive or negative?

Answer 19

the coordinates.

Answer 20

in*

Answer 21

Well if n is positive, then (n,n) is in quadrant I, (-n,n) is in quadrant II, (-n,-n) is in quadrant III


So if n is positive, then the answer is C(-n,-n)

Answer 22

omg how are you so smart

Answer 23

just a lot of practice

Answer 24

are you graduated from school?

Answer 25

So I'm guessing that was the correct answer? I wish it told you whether n was positive or not...

Answer 26

yes I'm in college

Answer 27

dang where do you go if thats not creepy

Answer 28

I'm not sure what you mean

Answer 29

oh you mean where do I go to college?

Answer 30

yeah

Answer 31

humboldt state university

Answer 32

wheres that?

Answer 33

in california

Answer 34

i guess its not well known, but it's still a great school

Answer 35

thats cool :)

Answer 36

yes, I like it a lot

Answer 37

okay another question

what is the most precise name for quadrilateral ABCD with vertices A(-5,2) B(-3,6) C(6,6) and D(4,2)

Parallelolgram
rectangle
rhombus
quadrilateral

Answer 38

Let me graph the points real quick, one sec

Answer 39

kk

Answer 40

If you plot the points and draw segments between them, you'll get what you see in the attached image.


So we get a parallelogram

Answer 41

Another way to do this is to compute the slopes and compare them. You'll find that the slopes of the opposite sides are equal. So this will confirm that we have a parallelogram.

Answer 42

okay i think i get it .

Answer 43

that's great

Answer 44

what is the most precise name for quadrilateral ABCD with vertices A(-5,-1) B(-5,3) C(-2,3) and D(-2,-1)

i graphed it but i think its wrong. i got a quadrilateral

Parallelolgram
rectangle
rhombus
quadrilateral

am i wrong? hahaha

Answer 45

well anything with four sides is a quadrilateral, so you're not wrong


but....that's not what they're looking for since there's a better term (quadrilateral is a bit vague in this context)

Answer 46

let me graph it real quick and post the pic for you

Answer 47

take a look at the attached, you'll find that each angle is 90 degrees but not all sides are equal to each other

So we have a rectangle.

Answer 48

damnn, i regraphed it and then i got that rectangle

Answer 49

so you probably lost a sign somewhere

Answer 50

but that's great that you got what I got

Answer 51

haha slowly getting it

Answer 52

lol there's no hurry, take all the time you need

Answer 53

lol i just very much appreciate you helping me i feel like i am annoying you.

Answer 54

no not at all

Answer 55

whats your name if you doont mind me asking

Answer 56

Jim

Answer 57

hhaha wow i feel like an idiot

Answer 58

lol that's ok, your brain is probably overloaded on too much math

Answer 59

it is lol =\

Answer 60

then that means it's time for a much needed break

Answer 61

noo i gotta get this done =\ i am just trying to get help on the hard problems

Answer 62

good point, it's always good to just get it done and over with asap

Answer 63

haha exactly okay i do not know how i solve this?

Answer 64

which one are you referring to?

Answer 65

Given: The coordinates of a rectangle DEFG are D(0,b) E(a,b) F(a,0) and G(0,0). Prove: The Diagnols of a rectangle are congruent.

As part of the proof, find the length of DF

A. sqr a-b
B. sqr a^2-b^2
C. sqr a^2+b^2
D. sqr a+b

Answer 66

The length of DF is the same as the distance between points D(0,b) and F(a,0) . To do this, we use the distance formula.


d = sqrt( (x1-x2)^2 + (y1-y2)^2 )

d = sqrt( (0-a)^2 + (b-0)^2 )

d = sqrt( (-a)^2 + (b)^2 )

d = sqrt( a^2 + b^2 )


So it looks like the answer is choice C

Answer 67

okay so i have 5 more problems like this do i follow the same steps you did for this one?

Answer 68

yes, if you're finding the length of a segment, you just use the distance formula to find the distance between the two endpoints

Answer 69

okay :)

Answer 70

alright heres a biggin, and i promise iam done asking you questions lol

Answer 71

lol don't worry, you're not annoying me

Answer 72

well i just hate how i dont understand this ughhhh if i can pass algebra with an A i dont understand why i can pass this geometry crapp

Answer 73

alg 2*

Answer 74

well geometry is definitely a lot different from algebra, so if you were used to algebra, then it's probably a whole different experience for you...so don't feel bad that you don't get everything at first

Answer 75

just keep at it and you'll get it eventually

Answer 76

thank god i am not going to college to be a math teacher, i'd fail lmao

Answer 77

lol well hopefully you'll go for something you love

Answer 78

i am :) i graduate in a year !

Answer 79

very cool :)

Answer 80

okay heres the question.

Answer 81

Given: The coordinates of isosceles trapezoid JKLM are J(-b, c) K(b,c) L(a,0) and M(-a,0)
Prove: The diagonals of an isosceles trapezoid are congruent .

As part of the proof fine the length KM
A: sqr (a+b)^2+c^2
B: sqr(-a+b)^2+c^2
C: sqr(a-b)^2+c^2
D: sqr a^2+b^2+c^2

Answer 82

Again, we're using the distance formula to find the distance between K and M


d = sqrt( (x1-x2)^2 + (y1-y2)^2 )


d = sqrt( (b-(-a))^2 + (c-0)^2 )


d = sqrt( (b+a)^2 + (c)^2 )


d = sqrt( (a+b)^2 + c^2 )


So it looks like the answer is choice A

Answer 83

alright that makes sense i just messed up i think i set my problem wrong

Answer 84

Perhaps you mixed up some signs?

Answer 85

like i look at your wor kk and then mine i am always off by like one step

Answer 86

i gotcha