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Is the following statement true or false (a^4)^(1/4)=a for every real number a.
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\[\sqrt[4]{a^4}=a\]
What happens if you put in a negative number?
you get a complex solution.
or you get a?... idk
Right about the complex solution, so that means it's not valid for EVERY real number a.
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Err, wait, sorry
Yeah I tried it and got a... or the number...
Take a=-1 \[^4\sqrt{(-1)^4}=^4\sqrt{1}=1\]
But 1 does not equal -1.
The fourth root of 1 is 1, because 1^4=1
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if 1 is not equal to -1... then a is not equal to a and there is no solution?
Close. \[a \neq ^4\sqrt{a^4}\] for negative numbers
Okay, Thank you!!!
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