Question

Solve the in equality x^2>9

Answer 1

The only solution is,

\[x = \sqrt{9} \]

Answer 2

and express the solution in terms of intervals

Answer 3

First, take the square root of both sides.
absolute value of {x}>(+/-)3
This is now two separate inequalities...
x<-3 and x>3.

Answer 4

\[\sqrt{x^2}>\sqrt{9}\]\[x>3\]

Answer 5

The given interval is (-infinity,-3) U (3, infinity)

Answer 6

thank you

Answer 7

Make sure when you take the square root of something you remember the absolute value signs and the plus or minus signs! =)

Answer 8

truth :)

Answer 9

Oh, yes, thank you

Answer 10

x > 3. :)