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Mathematics 14 Online
OpenStudy (anonymous):

someone please help me? :) the document is attached.

OpenStudy (anonymous):

OpenStudy (amistre64):

the operators should remind you of inequalities

OpenStudy (amistre64):

is d<e means; are all the elements of d contained within e, such that e has at least one more element than d

OpenStudy (amistre64):

the others are similar to that but have the underline representing that the sets can have the same elements in total as well

OpenStudy (amistre64):

part d tho rings a caution for me, the terminology used always threw me for a loop

OpenStudy (anonymous):

Okay, tell me if im right. D is a proper subset of E, because everything in D is included in E.

OpenStudy (amistre64):

equal sets contain the exact same elements; equivalent sets contain the same number of elements, but the elements can differ

OpenStudy (anonymous):

for part a.

OpenStudy (amistre64):

that is correct, proper subset meaning that E is bigger in number than D to begin with

OpenStudy (anonymous):

okay. and part b is true too right?

OpenStudy (amistre64):

yes, D is contained with in U or is equal to U, either condition is sufficient for truth

OpenStudy (anonymous):

because everything in D is a subset of U?

OpenStudy (amistre64):

yes

OpenStudy (anonymous):

im stumped on part c.. now

OpenStudy (amistre64):

Either F is contained within F, or is equal to F. true or false?

OpenStudy (anonymous):

true.

OpenStudy (amistre64):

i agree, its true.

OpenStudy (anonymous):

because F is F lol.. because all elements are the same?

OpenStudy (amistre64):

yep

OpenStudy (anonymous):

and F is not equivalent to D.

OpenStudy (amistre64):

terminology here; equivalent means: same number of elements.

OpenStudy (anonymous):

wait it is because there are 4 in each

OpenStudy (amistre64):

do F and D have the same number of elements? correct

OpenStudy (anonymous):

how would i answer the last one. would it be the number of elements too?

OpenStudy (amistre64):

there is some formula for that that I can never recall. but essentially its all the subsets that can be made from it; from 9 elements all the way down to no elements

OpenStudy (anonymous):

isn't it 2^n

OpenStudy (amistre64):

9c9 + 9c8 + 9c7 ... something like that 2^n sounds familiar, but I cant be sure

OpenStudy (amistre64):

2^n - 1 or +1 maybe

OpenStudy (anonymous):

so maybe it's 2^9

OpenStudy (amistre64):

if we gots 3 elements a,b,c the subsets are: abc ab ac bc a b c null 8 sets 2^3 = 8

OpenStudy (amistre64):

4elements would be: abcd abc abd acd bcd ab ac ad bc bd cd a b c d nul 16 sets; is that 2^4?

OpenStudy (amistre64):

2^n looks like its right

OpenStudy (anonymous):

So i just solve 2^9 and i get my last answer...

OpenStudy (amistre64):

yep

OpenStudy (anonymous):

thank you so much! your amazing lol:) I was so lost... thanks!

OpenStudy (amistre64):

you did fine :) good luck

OpenStudy (anonymous):

thanks!

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