Question

In a right triangle, 13 years ago

Answer 1

Find an equation for the line, in the general form, with the given properties (-8,1)(-6,-2)

Answer 2

that makes no sense?

Answer 3

how did you get root 10?

Answer 4

by pythagoras hypotenuse is
\[\sqrt{1^2+3^2}=\sqrt{10}\] and therefore
\[\sin(x)=\frac{3}{\sqrt{10}}\]

Answer 5

clear where \(\sqrt{10}\) came from?

Answer 6

I am honestly so lost :(

Answer 7

ok lets go slow

Answer 8

okay thank you :)

Answer 9

you are told \(\tan(x)=3\) and tangent is opposite over adjacent right?

Answer 10

yep

Answer 11

so the first thing you do is draw a right triangle as a reference

Answer 12

did that

Answer 13

how do i know which corner tan is?

Answer 14

the opposite over the adjacent is \(\tan(x)=3\) so the easiest way to label is put the "opposite" side as 3, and the adjacent side as 1

Answer 15

doesn't matter

Answer 16

just as long as you label the opposite side as 3, and the adjacent side as 1

Answer 17

because \(\tan(x)=3\) and \(\frac{3}{1}=3\)

Answer 18

okay and did you get 1 because its just x and not like 3x or something?

Answer 19

right it is the ratio you are concerned with
use \(\frac{3}{1}\)

Answer 20

okay and then you times both sides by 1 right?

Answer 21

now we get this picture