Need help writing the net ionic equation for NH3 + O2 --> NO + H2O
\[NH_3+O_2\rightarrow NO+H_2O\]first Balance the equation
\[4NH_3+5O_2\rightarrow 4NO+6H_2O\]
ima guess that nitric oxide is what your looking to focus on...
\[4NH _{3} + 5O _{2} \rightarrow 4NO + 3H _{2}O\] correct?
oh.. you already did it. haha
you got too many reactant hydrogen
wrong number of water molecules
next step is to find the ions
\[N ^{+3} + H _{3}^{-3} \rightarrow 4NO ^{-1} + 6H _{2}O\] I don't think this is correct but I gave it my best shot.
thats a rather advanced way to write ions... :O
The steps my teacher gave us says we're supposed to delete ions that don't change. Is there anything I'm supposed to delete here? I don't see any that stayed the same from the reactant side to the product side.
4NH3+5O2-> 4NO+6H2O here how id do it: 4NH3+5O2-> 4NO+6H2O break ions: 4N- + 4H3+ + 5O2 -> 4NO +6H2+ + 6O- keep the 4NO because its your wanted product so cancel all the other crap and theres no charge on the O because its a diatomic 4N- + 2O2 -> 4NO
The net ionic equation is the balanced chemical equation. 4NH3+5O2→4NO+6H2O This is because NH3, NO, and O2 are gases, not aqueous solutions. and H2O only slightly ionizes into H+ and OH-. The general rule for net ionics is to only include extensive ionization (past 0.1 M), which doesn't apply to any compounds in this equation.
I knew that........ :D
My brain. It feels betrayed. Haha thanks everyone.
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