Question

Solve the inequality \[(\frac{4}{3x+2}) ge (0)\] and express the solution as an interval.

Answer 1

\[\frac{4}{3x+2} \ge 0\]

Answer 2

changes sign where the denominator is 0, namely at \(-\frac{2}{3}\)

Answer 3

positive if \(x>-\frac{2}{3}\) negative otherwise

Answer 4

So \[x \ge -\frac{2}{3}\]

Answer 5

I mean yea not equal to...

Answer 6

make sure to answer with a strict inequality \(>\) rather than \(\geq\) because the denominator cannot be zero

Answer 7

Okay, thank you