Question

Solve the inequality \[\frac{4}{x^2+4}<0\] and express the solution as an interval.

Answer 1

numerator is always positive, and so is the denominator, so no solution

Answer 2

Yeah I knew there is no way possible this can be less than 0....

Answer 3

\(4>0\) and \(x^2\geq 0\) for all \(x\) and so \(x^2+4\geq 4\) for all \(x\) and therefore
\(\frac{4}{x^2+4}>0\) for all x

Answer 4

Thank you!!!

Answer 5

yw

Answer 6

wait, how'd you get that last part?

Answer 7

what last part?

Answer 8

how is \[x^2 \ge 0\]

Answer 9

because it is a square

Answer 10

if you square a positive number, the answer is positive
if you square a negative number, the answer is also positive
the only way to get something not positive is to square 0
that is why \(x^2\geq0\)

Answer 11

Oh... okay, wasn't reading it properly... thanks once again :)