Question

3log_{2}^\left(\begin{matrix}x-1\end{matrix}\right)+log_{4}=4

answer is 3
show me the process please?

Answer 1

\[3\log_{2}\left(
x−1
\right)+\log_{4}=4\]

Answer 2

no that can't be right. something is missing

Answer 3

sorry mah bad that second log suppose to be
\[3\log_{2}(x-1)+\log_{2}4=4\]

Answer 4

oop
i mean first off \(\log_2(4)=2\) yes?

Answer 5

so we have
\[3\log_2(x-1)+2=4\] and therefore
\[3\log_2(x-1)=2\]

Answer 6

still something is goofy because the answer is not 3

Answer 7

if you replace \(x\) by 3 you get
\[3\log_2(3-1)+2=4\]
\[3\log_2(2)+2=4\]
\[3+2=4\] and that is not right

Answer 8

was it
\[3\log_2(x-1)+\log_4(4)=4\]??

Answer 9

then 3 would be the right answer

Answer 10

\[\log_4(4)=1\]
\[3\log_2(x-1)+1=4\]
\[3\log_2(x-1)=3\]
\[\log_2(x-1)=1\]
\[x-1=2\]
\[x=3\]

Answer 11

log_{2}4=5...